3x(2x+3)=6x^2+9x

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Solution for 3x(2x+3)=6x^2+9x equation: 



3x(2x+3)=6x^2+9x

We move all terms to the left:

3x(2x+3)-(6x^2+9x)=0

We multiply parentheses

6x^2+9x-(6x^2+9x)=0

We get rid of parentheses

6x^2-6x^2+9x-9x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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